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DBV factor assignment can be audited through the use of the audit configuration of the DBV rule set that controls the assignment DBV factor assignment can also be audited in the same manner that auditing the execution of DBMS_SESSION or an application context s PL/SQL package, which is to AUDIT EXECUTE ON DVSYSSET_FACTOR To illustrate DBV factor assignment, consider the following scenario (see Figure 5-11) A web-based Sales History application is running on an application server The application uses a dedicated account for connection pool and the application uses DBMS_SESSIONSET_IDENTIFIER to assert the real end user for audit attribution To use DBV factor assignment in lieu of DBMS_ SESSIONSET_IDENTIFIER, we need to create a DBV factor and determine the conditions that must be met to authorize the assignment of this factor in a DBV rule set We can use database session context information that is available when ASO PKI/SSL authentication is used from the application server to the database as a basis for these conditions We can place some level of trust in the session because both the application server and database server must be configured to participate in a PKI trust relationship using Oracle wallets (something we have) If the organization s certificate authority (CA) and PKI controls are sound and the physical access to the machines is controlled, we can place an even greater level of trust in the use of this information The added benefit of the configuration is that all the network communications between the application server and the database server (in support of database session) are encrypted For the sake of brevity, let s assume we have configured ASO PKI/SSL authentication between our application server and database server NOTE If you would like more details on how to set up this type of authentication for the enterprise and a formal CA, read Oracle Metalink note 7365101 - Step by Step Guide to Configure SSL Authentication If you want to set up a development capability quickly using self-signed Oracle wallets, refer to Oracle Metalink note 7622861 - End to End Examples of Using SSL with Oracle s JDBC THIN Driver or the white paper SSL With Oracle JDBC Thin Driver available on the Oracle Technology Network (OTN) at www oraclecom/technology/tech/java/sqlj_jdbc/pdf/wp-oracle-jdbc_thin_ ssl_2007pdf These resources will walk you through how the steps to create and configure your Oracle wallets and the Oracle networking files for ASO PKI/SSL authentication.

To add two numbers x and y modulo N , we start with regular addition Since x and y are each in the range 0 to N 1, their sum is between 0 and 2(N 1) If the sum exceeds N 1, we merely need to subtract off N to bring it back into the required range The overall computation therefore consists of an addition, and possibly a subtraction, of numbers that never exceed 2N Its running time is linear in the sizes of these numbers, in other words O(n), where n = log N is the size of N ; as a reminder, our convention is to use the letter n to denote input size To multiply two mod-N numbers x and y, we again just start with regular multiplication and then reduce the answer modulo N The product can be as large as (N 1) 2 , but this is still at most 2n bits long since log(N 1)2 = 2 log(N 1) 2n To reduce the answer modulo N , we compute the remainder upon dividing it by N , using our quadratic-time division algorithm Multiplication thus remains a quadratic operation Division is not quite so easy In ordinary arithmetic there is just one tricky case division by zero It turns out that in modular arithmetic there are potentially other such cases as well, which we will characterize toward the end of this section Whenever division is legal, however, it can be managed in cubic time, O(n 3 ) To complete the suite of modular arithmetic primitives we need for cryptography, we next turn to modular exponentiation, and then to the greatest common divisor, which is the key to 25

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Part II:

Figure 14 Modular exponentiation function modexp(x, y, N ) Input: Two n-bit integers x and N , an integer exponent y Output: xy mod N if y = 0: return 1 z = modexp(x, y/2 , N ) if y is even: return z 2 mod N else: return x z 2 mod N

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