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This function installs a callback function that will be invoked during calls to sqlite3_exec(), sqlite3_step(), and sqlite3_get_table(). The intent of this function is to give applications a way to provide feedback to the user during long-running queries. The second argument (frq) specifies the frequency of the callback in terms of VDBE instructions. That is, the progress callback (provided in the third argument) will be called for every frq VDBE instruction performed in query execution. If a call to sqlite3_exec(), sqlite3_step(), or sqlite3_get_table() requires less than frq instructions to be executed, then the progress callback will not be invoked. The fourth argument is a pointer to application-specific data, which is passed back to the progress handler (as its one and only argument). If NULL is provided for the callback function argument, then the currently installed progress handler (if any) is disabled.

This is a myth that I would like to dispel once and for all: space is reused in an index The myth goes like this: you have a table, T, in which there is a column, X At some point, you put the value X=5 in the table Later you delete it The myth is that the space used by X=5 will not be reused unless you put X=5 back into the index later The myth states that once an index slot is used, it will be there forever and can be reused only by the same value A corollary to this is the myth that free space is never returned to the index structure, and a block will never be reused Again, this is simply not true The first part of the myth is trivial to disprove.

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All we need to do is to create a table like this: ops$tkyte@ORA11GR2> create table t ( x int, constraint t_pk primary key(x) ); Table created ops$tkyte@ORA11GR2> insert into t values (1); 1 row created ops$tkyte@ORA11GR2> insert into t values (2); 1 row created ops$tkyte@ORA11GR2> insert into t values (9999999999); 1 row created ops$tkyte@ORA11GR2> analyze index t_pk validate structure; Index analyzed ops$tkyte@ORA11GR2> select lf_blks, br_blks, btree_space 2 from index_stats; LF_BLKS BR_BLKS BTREE_SPACE ---------- ---------- ----------1 0 7996 So, according to the myth, if I delete from T where X=2, that space will never be reused unless I reinsert the number 2 Currently, this index is using one leaf block of space If the index key entries are never reused upon deletion, and I keep inserting and deleting and never reuse a value, this index should grow like crazy Let s see: ops$tkyte@ORA11GR2> begin 2 for i in 2 ..

999999 3 loop 4 delete from t where x = i; 5 commit; 6 insert into t values (i+1); 7 commit; 8 end loop; 9 end; 10 / PL/SQL procedure successfully completed ops$tkyte@ORA11GR2> analyze index t_pk validate structure; Index analyzed..

If the progress callback returns a nonzero value, the current query will be immediately terminated, and any database changes will be rolled back. If the query was part of a larger transaction, then the transaction is not rolled back and remains active. The sqlite3_exec() call in that case will return SQLITE_ABORT.

ops$tkyte@ORA11GR2> select lf_blks, br_blks, btree_space 2 from index_stats; LF_BLKS BR_BLKS BTREE_SPACE ---------- ---------- ----------1 0 7996 This shows the space in the index was reused As with most myths, however, there is a nugget of truth in there The truth is that the space used by that initial number 2 (in between 1 and 9,999,999,999) would remain on that index block forever The index will not coalesce itself This means if I load a table with values 1 to 500,000 and then delete every other row (all of the even numbers), there will be 250,000 holes in the index on that column Only if I reinsert data that will fit onto a block where there is a hole will the space be reused Oracle will make no attempt to shrink or compact the index This can be done via an ALTER INDEX REBUILD or COALESCE command.

On the other hand, if I load a table with values 1 to 500,000 and then delete from the table every row where the value was 250,000 or less, I would find the blocks that were cleaned out of the index were put back onto the FREELIST for the index This space can be totally reused If you recall, this was the second myth: index space is never reclaimed It states that once an index block is used, it will be stuck in that place in the index structure forever and will only be reused if you insert data that would go into that place in the index anyway We can show that this is false as well First, we need to build a table with about 500,000 rows in it.

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